An ice cream cone is a composite solid: a cone of height 12 cm and radius 3 cm, topped with a hemisphere (half sphere) of the same radius. Find the total volume of the ice cream (cone + hemisphere).
Cone: ( V = \frac13 \pi r^2 h = \frac13 \pi \times 3^2 \times 12 = \frac13 \pi \times 9 \times 12 = 36\pi , \textcm^3 ) Hemisphere: ( V = \frac12 \times \frac43 \pi r^3 = \frac23 \pi \times 3^3 = \frac23 \pi \times 27 = 18\pi , \textcm^3 ) Total = ( 36\pi + 18\pi = 54\pi , \textcm^3 ) ≈ ( 169.65 , \textcm^3 ) area and volume exercise form 3
Base area = ( \pi r^2 = \frac227 \times 0.7^2 = \frac227 \times 0.49 = 22 \times 0.07 = 1.54 , \textm^2 ) Curved surface area = ( 2\pi r h = 2 \times \frac227 \times 0.7 \times 1.5 = 2 \times 22 \times 0.1 \times 1.5 = 2 \times 3.3 = 6.6 , \textm^2 ) Total = ( 1.54 + 6.6 = 8.14 , \textm^2 ) An ice cream cone is a composite solid: